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An ideal coil of 10H is connected in ser...

An ideal coil of 10H is connected in series with a resistance of `5(Omega)` and a battery of 5V. 2second after the connections is made, the current flowing in ampere in the circuit is

A

`(I-e)`

B

`e`

C

`e^(-1)`

D

`(I-e^(-1))`

Text Solution

Verified by Experts

The correct Answer is:
D
`I_(0) = (E)/(R ) = 1A , tau = (L)/(R ) = (10)/(5) = 2s, :. (I = 1-e^(-1))A`
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