A `120 V, 60 Hz` a.c. power is connected `800 Omega` non-inductive resistance and unknown capacitance in series. The voltage drop across the resistance is found to be `102 V`, then voltage drop across capacitor is

Options

A. `8 V`
B. `102 V`
C. `63 V`
D. `55 V`

Answer

3

Explanation

`V^(2) = V_(R )^(2) + V_(C )^(2)`
`V_(C )^(2) = V^(2) - V_(R )^(2)`
`V_(C )^(2) = (120)^(2) - (102)^(2)`
`V_(C ) = 63 V`