For the `LCR` circuit, shown here, the current is observed to lead the applied voltage. An additional capacitor `C'`, when joined with the capacitor `C` present in the circuit, makes the power factor of the circuit unity. The capacitor `C'` must have been connected in:

Options

A. series with `C` and has magnitude `(C )/((omega^(2) LC - 1))`
B. series with `C` and has a magnitde `(1 - omega^(2) LC)/(omega^(2) L)`
C. parallel with `C` and has a magnitude `(1 - omega^(2) LC)/(omega^(2) L)`
D. parallel with `C` and has a magnitude `(C )/((omega^(2) LC - 1))`

Answer

3

Explanation

`X_(L) = X_(C )` for `cos phi = 1`