Instantaneous values of current and e.m.f in an AC circuit are `I=I//sqrt(2)sin 314` tamp and `E=sqrt(2)sin(314t-pi//6)V` respectively. The phase difference between `E` and `I` will be

Options

A. `- (pi)/(6)` rad
B. `- (pi)/(3)`
C. `(pi)/(6)`
D. `(pi)/(3)` rad

Answer

A

Explanation

`I = (1)/(sqrt(2)) sin 314 t` , `E = sqrt(2) sin (314 t - (pi)/(6))`
with respect to current, the emf is lagging.
So phase difference is `phi = - (pi)/(6)`