An electric bulb is designed to operate ...

An electric bulb is designed to operate at `12` volts `DC`. If this bulb is connected to an AC source and gives normal brightness, what would be the peak voltage of the source?

`37 V`

`17 V`

`18 V`

`10 V`

Text Solution

Verified by Experts

The correct Answer is:

`i_("rms") = (i_(0))/(sqrt(2))`, `V_(DC) = (V_(0))/(sqrt(2))`
`12(1.4) = 16.8 ~~ 17`

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