A coil having an inductance of `1//pi` henry is connected in series with a resistance of `300 Omega`. If 20 volt from a 200 cycle source are impressed across the combination, the value of the phase angle between the voltage and the current is :

Options

A. `"tan"^(-1) (5)/(4)`
B. `"tan"^(-1) (4)/(5)`
C. `"tan"^(-1) (3)/(4)`
D. `"tan"^(-1) (4)/(3)`

Answer

D

Explanation

`X_(L) = 2 pi f L = 2 pi xx 200 xx (1)/(pi) = 400 Omega`
`R = 300 Omega`
`tan phi = (X_(L))/(R ) = (400)/(300) = (4)/(3)`
`implies phi = tan^(-1) ((4)/(3))`