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In the circuit as shown in the figure, i...

In the circuit as shown in the figure, if value of `R = 60 Omega`, then the current flowing through the condenser will be

A

`0.5 A`

B

`0.25 A`

C

`0.75 A`

D

`1.0 A`

Text Solution

Verified by Experts

The correct Answer is:
B
`I =` current flowing through condenser`//`capacitor. `R,L,C` are connected in series. So some current flows through `R`.
`V_(R) = IR implies 15 = 1 xx 60 implies l=(1)/(4) = 0.25 A`
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    B
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