In the circuit as shown in the figure, if value of `R = 60 Omega`, then the current flowing through the condenser will be

Options

A. `0.5 A`
B. `0.25 A`
C. `0.75 A`
D. `1.0 A`

Answer

B

Explanation

`I =` current flowing through condenser`//`capacitor. `R,L,C` are connected in series. So some current flows through `R`.
`V_(R) = IR implies 15 = 1 xx 60 implies l=(1)/(4) = 0.25 A`