In a series `C-R` circuit shown in figureure, the applied voltage is `10 V` and the voltage across capacitor is found to`8 V`. The voltage across `R`, and the phase difference between current and the applied voltage will respectively be
.

Options

A. `6 V, tan^(-1) ((4)/(4))`
B. `3V, tan^(-1)((3)/(4))`
C. `6V, tan^(-1)((5)/(3))`
D. `3V, tan^(-1)((4)/(3))`

Answer

A

Explanation

`V^(2) = V_(R )^(2) + V_(C )^(2) implies V_(R ) = 6` volt
`phi = tan^(-1) ((X_(C ))/(R )) = tan^(-1) ((V_(C ))/(V_(R )))`
`tan^(-1) ((8)/(6)) = tan^(-1) ((4)/(3))`