The impedance of a sereis `RL` circuit is same as the series `RC` circuit when connected to the same `AC` source separately keeping the same resistance. The frequency of the source is

Options

A. `(1)/(sqrt(LC))`
B. `(1)/(2pi sqrt(LC))`
C. `(R )/(L)`
D. `(1)/(RC)`

Answer

B

Explanation

The impedance in `RL` circuit is same as the `RC` circuit:
`:. sqrt(R^(2) + omega^(2) L^(2)) = sqrt(R^(2) + (1)/(omega^(2) L^(2)))`
`implies omega^(2) = (1)/(LC)` or `f = (1)/(2 pi sqrt(LC))`