A current source sends a current `I=(i_0) cos (omegat)`, When connected across an unknown load, it gives a voltages output of `v=v_(0)sin [omega t+(pi//4)]` across that load. Then the voltage across the current source may bebroaught in phase with the current through it by

Options

A. Connectinng an inductor in series with the load
B. Connecting a capacitor in series with the load
C. Connecting a capacitor in parallel with the load
D. Connecting a capacitor in parallel with the load

Answer

B

Explanation

`v = v_(0) sin (omega t + pi // 4) = v_(0) cos (omega t - (pi)/(4))`
Since `V` lags current, inductor canbring it in phase with current.