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In R-L-C series circuit, we have same cu...

In `R-L-C` series circuit, we have same current at angular frequencies `omega_(1)` and `omega_(2)`. The resonant frequency of circuit is

A

`(omega_(1)^(2))/(omega_(2))`

B

`(omega_(2)^(2))/(omega_(1))`

C

`sqrt(omega_(1) omega_(2))`

D

`omega_(1) + omega_(2)`

Text Solution

Verified by Experts

The correct Answer is:
C

`omega_(1) L - (1)/(omega_(1) C) = omega_(2) L - (1)/(omega_(2) C)`
Solving `omega_(1) omega_(2) = (1)/(sqrt(LC)) = omega_(0)^(2)`
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