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When two A.C generators of emfs V(1) and...

When two `A.C` generators of emfs `V_(1)` and `V_(2)` and same frequency connected in series, the emf across `A` and `B` is `(phi =` phase angle difference between the generators):

A

`(V_(1) + V_(2))/(2)`

B

`sqrt(V_(1) + V_(2))`

C

`sqrt(V_(1)^(2) + V_(2)^(2) + 2 V_(1) V_(2) cos phi)`

D

`sqrt(V_(1)^(2) + V_(2)^(2))`

Text Solution

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The correct Answer is:
C
Apply parallelogram law
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