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When an ac source of emfe=E(0) sin (100 ...

When an ac source of emf`e=E_(0) sin (100 t)` is connected across a circuit, the phase difference between emf e and currnet I in the circuit is observed to be `(pi)//(4)` as shown in fig. If the circuit consists possibly only of R-C or R-C of L-R series, find the relationship find the relationship between the two elements.

A

`R = 1 k Omega, C = 10 mu F`

B

`R = 1 k Omega, C = 1 mu F`

C

`R = 1 k Omega, H = 10 H`

D

`R = 1 k Omega, L = 1 H`

Text Solution

Verified by Experts

The correct Answer is:
C

From the graph current leads emf. Hence the circuit should be `RC`. For the circuit `"tan" (pi)/(4) = (1)/(omega CR)`
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