The time taken by an `AC` of `50 Hz` in reaching from zero to its maximum value will be

Options

A. `0.5 s`
B. `0.005 s`
C. `0.05 s`
D. `5 s`

Explanation

To find the time taken by an AC of 50 Hz in reaching from zero to its maximum value, we can follow these steps:

### Step 1: Understand the relationship between frequency and time period
The frequency (f) of an AC signal is related to its time period (T) by the formula:
\[ T = \frac{1}{f} \]
where:
- \( T \) is the time period in seconds,
- \( f \) is the frequency in hertz (Hz).

### Step 2: Calculate the time period for 50 Hz
Given that the frequency \( f = 50 \) Hz, we can calculate the time period \( T \):
\[ T = \frac{1}{50} = 0.02 \text{ seconds} \]

### Step 3: Determine the time taken to reach maximum value
In one complete cycle of an AC waveform, the time taken to go from zero to maximum value is \( \frac{T}{4} \). This is because:
- The waveform starts at zero,
- It reaches its maximum value at \( \frac{T}{4} \),
- Then it goes back to zero at \( \frac{T}{2} \).

### Step 4: Calculate \( \frac{T}{4} \)
Now, we can calculate the time taken to reach the maximum value:
\[ \text{Time to reach maximum} = \frac{T}{4} = \frac{0.02}{4} = 0.005 \text{ seconds} \]

### Final Answer
The time taken by the AC of 50 Hz in reaching from zero to its maximum value is **0.005 seconds**.

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