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In an L-C-R series circuit, R = sqrt(5...

In an `L-C-R` series circuit,
`R = sqrt(5) Omega, = 9 Omega, X_(C ) = 7 Omega`. If applied voltage in the circuit is `50 V` then impedance of the circuit in ohm will be

A

2

B

3

C

`2 sqrt(5)`

D

`3 sqrt(5)`

Text Solution

Verified by Experts

The correct Answer is:
2
Impedance, `Z = R + X_(c ) + X_(L)`
`= (5 sqrt(5 i) = 7 j + 9 j) = sqrt(5 i) + 2 j`
`|Z| = sqrt(5 + 4) = sqrt(9) = 3`
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