Show that `0. 2353535......=0.2bar35 ` can be expressed in the form `p/q ,\ ` where `p\ a n d\ q` integers and `q\ !=\ 0.`

Explanation

Let `x=0.2bar35`
Since there is one digit after decimal and not under the bar, multiply by 10 on both sides.
`10x=0.2bar35xx10`
`10x=2.bar35`
`10x=2+0.bar35`
`10x=2+35/99`
​`10x=(2xx99+35)/99=233/99`
​`x=233/990`
Hence, `0.2bar35=233/990`