The number of consecutive zeros in `2^3xx\ 3^4xx\ 5^4xx\ 7,` is (a) 3 (b) 2 (c) 4 (d) 5

Explanation

We can make zero only by multiplying `2` and `5`, like`2 xx 5=10`
`2 xx 2 xx 5=20`
so we can conclude here multiplication of `2` and `5` always brings `0`, however no. of zeros always equal to the no of `2` and `5` in the expression, whichever is minimum.
So, here comes at the question, we haveto find consecutive no. of zeros, for this we have to find the find the no. of `2` and `5` in the expression and answer will be minimum one.so in the given expression ,no. of `2's =3` and no. of `5's = `4`
Hence, answer is `3`, we can make `3` consecutive zeros by solving this expression.