The rationalisation factor of `sqrt(3)` is (a)`-sqrt(3)` (b) `1/(sqrt(3))` (c) `2sqrt(3)` (d) `-2sqrt(3)`

Explanation

Solution:
General form
`= a + b sqrt(c)`
`= 0 +1sqrt(3)`
`0+sqrt(3)`
Rationalisation factor:
`a +b sqrt(c)`
`=>a - b sqrt(c)`
`=0 + sqrt(3)`
`=>0 -sqrt(3)`
`=-sqrt(3)`
Hence the correct answer is option `a = -sqrt(3)`