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Find the value of 4x^2+y^2+25 z^2+4x y-1...

Find the value of `4x^2+y^2+25 z^2+4x y-10 y z-20 z x` when `x=4,\ y=3` and `z=2`

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Given:
`x=4, y=3` and `z=2`
`4x^2+y^2+25z^2+4xy-10yz-20zx`
`4(4)^2+(3)^2+25(2)^2+4(4)(3)-10(3)(2)-20(2)(4)`
`=64=9+100+48-60-160=1`
`therefore 4x^2+y^2+25z^2+4xy-10yz-20zx=1`
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