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Evaluate: (0. 2)^3-\ (0. 3)^3+\ (0. 1)^3...

Evaluate: `(0. 2)^3-\ (0. 3)^3+\ (0. 1)^3`

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To evaluate the expression \( (0.2)^3 - (0.3)^3 + (0.1)^3 \), we can use the identity for the sum of cubes. ### Step 1: Identify A, B, and C Let: - \( A = 0.2 \) - \( B = -0.3 \) - \( C = 0.1 \) ...
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Knowledge Check

  • What is the value of ((0.3)^(3)-(0.1)^(3))/([(0.3)^(2)+(0.1)^(2)+(0.3)xx (0.1)]) ?

    A
    `0.4`
    B
    `0.1`
    C
    `0.5`
    D
    `0.2`
  • Find the value of : (0.98)^3+(0.02)^3 + 3xx 0.98 xx 0.02-1

    A
    1.98
    B
    1.09
    C
    1
    D
    0
  • Value of (( 0. 5) ^( 0) - ( 0. 1) ^(-1))/( ( (3)/(4) ) ^( -1) ( (3)/(2)) ^(3) + ((-1)/( 3)) ^( -2)) is

    A
    `3//2`
    B
    `-2//3`
    C
    `-3//2`
    D
    `2//3`
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    without actually calculating , the cubes , find the valuse of (i) ((1)/(2))^(3)+((1)/(3))^(3)-((5)/(6))^(3) (ii) (0.2)^(3)-(0.3)^(3)+(0.1)^(3)

    Prove that: ((0. 6)^0- (0. 1)^(-1))/((3/8)^(-1) (3/2)^3+ (-1/3)^(-1))= -3/2

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    If A =((0.1)^3+(0.2)^3+(0.3)^3+3(0.005 + 0.016 + 0.027) + 0.036)/((0.1)^2+(0.2)^2+ (0.3)^2+0.04 + 0.06 + 0.12) ,then the value of 60A is: यदि A =((0.1)^3+(0.2)^3+(0.3)^3+3(0.005 + 0.016 + 0.027) + 0.036)/((0.1)^2+(0.2)^2+ (0.3)^2+0.04 + 0.06 + 0.12) है, तो 60A का मान क्या होगा ?

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