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`a(a+b)^3-3a^2b(a+b)`

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`a(a+b)^3-3a^2b(a+b)`
Taking `(a + b)` common in two terms
`=(a+b){a(a+b)^2-3a^2 b}`
Now using:
`(a+b)^2=a^2+b^2+2ab`
`=(a+b){a(a^2+b^2+2ab)-3a^2b}`
`=(a+b){a^3 +ab^2+2a^2b-3a^2b`
`=(a+b){a^3+ab^2-a^2b}`
`=(a+b)a{a^2 +b^2-ab}`
`=a(a+b)(a^2+b^2-ab)`
`therefore a(a + b)^3-3a^2b(a+b)=a(a+b)(a^2+b^2-ab)`
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