Home
Class 9
MATHS
Factorize: x(x-2)(x-4)+4x-8...

Factorize: `x(x-2)(x-4)+4x-8`

Text Solution

Verified by Experts

`x(x-2)(x-4)+4x-8`
`=x(x-2)(x-4)+4(x-2)`
Taking `(x-2)` common in both terms
`=(x-2){x(x-4)+4}`
`=(x-2){x^2-4x+4}`
Now splitting middle term of `x^2-4x+4`
`=(x-2){x^2 -2x-2x+4}`
`=(x-2){x(x-2)-2(x-2)}`
`=(x-2){(x-2)(x-2)}`
`=(x-2)(x-2)(x-2)`
`=(x-2)^3`
`therefore x(x-2)(x-4)+4x-8=(x-2)^3`
Promotional Banner

Topper's Solved these Questions

  • EXPONENTS OF REAL NUMBER

    RD SHARMA|Exercise All Questions|186 Videos

  • FACTORIZATION OF POLYNOMIAL

    RD SHARMA|Exercise All Questions|220 Videos

Similar Questions

Explore conceptually related problems

Factorize 3x^(2)-x-4

factorize : x^4+(4)/(x^4)

Factorize 9x^(2)+12x+4

Factorize x^(2)+(x)/(4)-(1)/(8)

Factorize x^2-4x-21 .

Factorize: x^(2)+8x+15 (ii) x^(4)+x^(2)+1 (iii) x^(4)+4

Factorize :(x^(2)-4x)(x^(2)-4x-1)-20

Factorize: x^(2)+8x+16( ii) 4a^(2)-4a+1

Factorize 1+x^(4)+x^(8)