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Factorize: (2a+1)^3+\ (a-1)^3...

Factorize: `(2a+1)^3+\ (a-1)^3`

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We have,`(2a+1)^3+(a-1)^3= {(2a+1)+(a-1)} {(2a + 1)^2-(2a + 1)(a−1)+(a−1)^2}`
`[ x^3 + y^3 = (x + y)(x^2 − xy + y^2)]`
= `(2a+1+a-1){(4a^2+4a+1)-(2a^2-2a+a-1)+(a^2-2a+1)}`
`[(x + y)^2 = x^2 + 2xy + y^2]`
= `3a(4a^2+4a+1-2a^2+a+1+a^2-2a+1)`
`=3a(3a^2+3a+3)`
`=9a(a^2+a+1)`
`:.(2a + 1)^3 + (a − 1)^3=9a(a^2 + a + 1)`
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