Factorize: `a^6-b^6`

Explanation

"Solution
`a^6-b^6 = (a^2)^3 - (b^2)^3`
Using,`(a^3 − b^3) = (a−b)(a^2 + ab + b^2)`
`=(a^2 − b^2)[(a^2)^2 + a^2b^2 + (b^2)^2]`
`=(a + b)(a−b)[(a^2)^2 + 2a^2b^2+(b^2)^2-a^2b^2]`
`=(a + b)(a−b)[(a^2 + b^2)^2 − a^2b^2]`
`= (a + b)(a − b)[(a^2 + b^2+ ab)(a^2 + b^2 − ab)]`"