Factorize: `8x^3+27 y^3+z^3-18 x y z`

Explanation

Given :
`8x^3+27 y^3+z^3-18 x y z=(2x)^3+(3y)^3+z^3−3(2x)(3y)(z)`
using, `[x^3+y^3+z^3−3xyz=(x+y+z)(x^2+y^2+z^2−xy−yx−zx)]`
`8x^3+27 y^3+z^3-18xyz=(2x+3y+z)(4x^2−6xy−2xz+9y^2−3yz+z^2)`