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Factorize: (2x-3y)^3+(4z-2x)^3+(3y-4z)^3...

Factorize: `(2x-3y)^3+(4z-2x)^3+(3y-4z)^3`

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To factorize the expression \((2x-3y)^3 + (4z-2x)^3 + (3y-4z)^3\), we can use the identity for the sum of cubes. The identity states that if \(a + b + c = 0\), then: \[ a^3 + b^3 + c^3 = 3abc \] ### Step-by-step Solution: ...
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