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Factorize: (x/2+y+z/3)^3+\ \ (x/3-(2y)/3...

Factorize: `(x/2+y+z/3)^3+\ \ (x/3-(2y)/3+z)^3+(-(5x)/6-y/3-(4z)/3)^3`

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To factorize the expression \((\frac{x}{2} + y + \frac{z}{3})^3 + (\frac{x}{3} - \frac{2y}{3} + z)^3 + (-\frac{5x}{6} - \frac{y}{3} - \frac{4z}{3})^3\), we can use the identity for the sum of cubes. The identity states that if \(a + b + c = 0\), then: \[ a^3 + b^3 + c^3 = 3abc \] ### Step-by-Step Solution: ...
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