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Factorize: (a-3b)^3+(3b-c)^3+(c-a)^3...

Factorize: `(a-3b)^3+(3b-c)^3+(c-a)^3`

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To factorize the expression \((a-3b)^3+(3b-c)^3+(c-a)^3\), we can use the identity for the sum of cubes. The identity states that if \(A + B + C = 0\), then: \[ A^3 + B^3 + C^3 = 3ABC \] ### Step-by-Step Solution: ...
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