The value of `((2. 3)^3-\ 0. 027\ )/((2. 3)^2+\ 0. 69+0. 09)` is (a)2 (b) 3 (c) 2.327 (d) 2.273

Explanation

We have to find the value of `((0.013)^³ + (0.007)^³) / ((0.013)^² - 0.013 x 0.007 + (0.007)^²) `by using the identity : `a^³ + b^³ = (a + b)\(a^² - ab + b^²)`
`= a^³ + b^³/a^² - ab + b^²`
`= ((a + b)\(a^² - ab + b^²))/(a^² - ab + b^²)`
`= a + b`
Here `a = 0.013 and b = 0.007`
`= 0.013 + 0.007`
`= 0.02`
Hence the value of `((0.013)^³ + (0.007)^³) / ((0.013)^² - 0.013 x 0.007 + (0.007)^² )`is ` 0.02.`