Find the integral roots of the polynomial `f(x)=x^3-6x^2+11 x-6`

Explanation

`f(x)=x^3-6x^2+11 x-6`, if we put x=1
`=>f(1)=1^3-6(1)^2+11(1)-6`
`=>1-6+11-6`
`=>f(1)=0`
so, (x-1) is a factor of x.
Similarly ,for x=2 and x=3.
`(x-1)(x-2)(x-3)` is a factor of x.