Find the rational roots of the polynomial `2x^3+3x^2-11 x-6`

Explanation

`=>2x^3+3x^2-11 x-6=0`
`=>2x^3+2x^2-x^2+x-12x+6=0`
`=>2x^2(x-1)-x(x-1)-6(2x-1)=0`
`=>(2x^2-x)(x-1)-6(2x-1)=0`
`=>x(2x-1)(x-1)-6(2x-1)=0`
`=>(2x-1)(x^2-x-6)=0`
`=>(2x-1)(x-3)(x+2)=0`
so,the roots are,`x=1/2,x=3,x=-2`.