If `x=0` and `x=-1` are the roots of the polynomial `f(x)=2x^3-3x^2+a x+b ,` find the value of `a` and `b`

Explanation

`x=0,f(x)=2x^3-3x^2+a x+b=0`
`=>2(0)^3-3(0)^2+a(0)+b=0`
`b=0`
`x=-1,f(x)=2(-1)^3-3(-1)^2+a (-1)+b=0`
`=>-2-3-a+b=0`
`=>b-a=5`
`b=0 and a=-5`
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