Find the integral roots of the polynomial `f(x)=x^3-6x^2+11 x-6`

Explanation

Put,` x=–1,
p(–1) =(–1) ^3+6(–1) ^2
+11(–1)+6`
`=>–1+6–11+6=0`
(x+1) is a factor of p(x)
So, we can break up terms of p(x) as follows.`p(x)=x ^3+6x ^2+11x+6`
Therefore, the integral roots of the given equation is find out as:

`p(x)=0,(x+1)(x+2)(x+3)=0`
`x=−1,−2,−3`