f(x)=9x^3-3x^2+x-5, g(x)=x-2/3...

`f(x)=9x^3-3x^2+x-5, g(x)=x-2/3`

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"`F(x) = 9x^3-3x^2+x-5, g(x) = x - 2/3`
Put `g(x) = 0`
⇒ `x - 2/3 = 0` or `x = 2/3`
Remainder = `f(2/3)` Now,
`f(2/3) = 9(2/3)^3 - 3(2/3)^2+(2/3)-5`
=`8/3-4/3+2/3-5/1`
=` -3`

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