`f(x)=x^3-6x^2+11 x-6;g(x)=x-3`

Explanation

1409702 If `g(x)` is a factor of `f(x)`, then the remainder will be zero that is `g(x)=0`
`g(x)=x-3=0` or `x=3`
Remainder`=f(3)`
Now,
`f(3)=(3)^3–6(3)^2+11x^3–6`
`=27–54+33–6=60-60`
`=0`
`therefore g(x)` is a factor of `f(x)`.