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If x^3+6x^2+4x+k , is exactly divisible ...

If `x^3+6x^2+4x+k` , is exactly divisible by `(x+2)`, then the value of k is:

`x+2=0, x=-2`
`(-2)^3+6(-2)^2+4(-2)+k=0`
`-8+24-8+k=0`
`8+k=0`
`k=-8`

Text Solution

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`x+2=0, x=-2`
`(-2)^3+6(-2)^2+4(-2)+k=0`
`-8+24-8+k=0`
`8+k=0`
`k=-8`
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