If `(x-1)` is a factor of polynomial `f(x)` but not of `g(x)` , then it must be a factor of (a)`f(x)g(x)` (b) `-f\ (x)+\ g(x)` (c)`f(x)-g(x)` (d) `{f(x)+g(x)}g(x)`
if (x -1) is a factor of polynomial f(x) but not of g(x)
Then it must be a factor of multiplication of f(x) and g(x). i.e `f(x)g(x)`
.Option A is correct.

Explanation

if (x -1) is a factor of polynomial f(x) but not of g(x)
Then it must be a factor of multiplication of f(x) and g(x). i.e `f(x)g(x)`
.Option A is correct.