If ray O C stands on line A B such that ...

If ray `O C` stands on line `A B` such that `/_A O C=/_C O B` , then show that `/_A O C=90^@`

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We are given that: AB is a straight line in which OC is standing means OC is perpendicular to AB.
So, OC perpendicular to AB then, O is the mid point of AB,
` /_ BOC= /_ AOC
BOC= 90` degree because it is perpendicular to AB.
/_BOC + /_ AOC =180@ (linear pair).
`2 /_AOC = 180` degree.
` /_AOC =180/2 = 90`degree.
Then, angle `BOC =90` degree.
Hence proved.

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