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Domain and range of f (x) = (|x-3|)/(x-3...

Domain and range of `f (x) = (|x-3|)/(x-3)` are respectively

A

`R, [-1,1]`

B

`R- {3}, {1,-1}`

C

`R ^(+),R`

D

None of these

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The correct Answer is:
To find the domain and range of the function \( f(x) = \frac{|x-3|}{x-3} \), we will analyze the function step by step. ### Step 1: Determine the Domain The domain of a function is the set of all possible input values (x-values) for which the function is defined. 1. The function \( f(x) = \frac{|x-3|}{x-3} \) is defined for all \( x \) except where the denominator is zero. 2. Set the denominator equal to zero to find the restriction: \[ x - 3 = 0 \implies x = 3 \] 3. Therefore, the function is undefined at \( x = 3 \). Thus, the domain of \( f(x) \) is: \[ \text{Domain} = \{ x \in \mathbb{R} : x \neq 3 \} \] ### Step 2: Determine the Range To find the range, we analyze the behavior of the function based on the value of \( x \). 1. **Case 1: When \( x \geq 3 \)** - In this case, \( |x-3| = x-3 \). - Therefore, \[ f(x) = \frac{x-3}{x-3} = 1 \quad \text{(for } x > 3\text{)} \] - At \( x = 3 \), the function is undefined. 2. **Case 2: When \( x < 3 \)** - Here, \( |x-3| = -(x-3) = 3-x \). - Thus, \[ f(x) = \frac{3-x}{x-3} = \frac{-(x-3)}{x-3} = -1 \quad \text{(for } x < 3\text{)} \] From the analysis: - For \( x \geq 3 \), \( f(x) = 1 \). - For \( x < 3 \), \( f(x) = -1 \). Thus, the range of \( f(x) \) is: \[ \text{Range} = \{ -1, 1 \} \] ### Final Answer - **Domain**: \( \{ x \in \mathbb{R} : x \neq 3 \} \) - **Range**: \( \{ -1, 1 \} \) ---
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TARGET PUBLICATION-SETS, RELATIONS AND FUNCTIONS-CRITICAL THINKING
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