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The equation of the hyperbola whose foci...

The equation of the hyperbola whose foci are (6.5), (-4,5) and eccentricity 5/4 is

A

`((x-2)^(2))/( 16) -((y-5)^(2))/(9) =1`

B

`((x-5)^(2))/(16)-((y -5)^(2))/(9) =1`

C

`((x-1)^(1))/(16) -((y-5)^(2))/(9) =-1`

D

`((x-1)^(2))/(9) - ((y-5)^(2))/(16) =1`

Text Solution

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The correct Answer is:
A
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TARGET PUBLICATION-CIRCLE AND CONICS -CRITICAL THINKING
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