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Find the equation of the parabola whose ...

Find the equation of the parabola whose focus is (5,3) and directrix is the line 3x-4y+1=0.

A

`(4x + 3y )^(2) - 256 x- 142y + 849=0`

B

`(4x -3y )^(2) -256 x-142 y + 849=0`

C

`(3x+ 4y)^(2) -142x -256y + 849=0`

D

`(3x -4y)^(2) -256-142y + 849 =0`

Text Solution

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The correct Answer is:
A
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TARGET PUBLICATION-CIRCLE AND CONICS -COMPETITIVE THINKING
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  6. Eccentricity of the parabola x^2-4x-4y+4=0 is

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  9. Vertex of the parabola x ^(2) +4x + 2y -7=0 is

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  10. The focous of the parabola y = 2x ^(2) + x is

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  11. The focus of the conic x ^(2) -6x + 4y +1=0 is

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  12. A line cuts the X-axis at A (5,0) and the Y-axis at B(0,-3). A variabl...

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  13. The distance between the vertex and the focus of the parabola x ^(2) -...

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  14. Equation of the directrix of the parabola y^(2)+4x+2=0 is

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  15. The equation of the directrix of the parabola x ^(2) + 8y -2x =7 is

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  16. For the parabola y ^(2) +6y -2x =-5 I) the vertex is (-2, -3) II) ...

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  17. The two parabolas x^2= 4y and y^2=4x meet in two distinct points. One...

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  18. Let O be the vertex and Q be any point on the parabola,x^2=""8y . I...

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  19. The cartesian co - ordinates of the point on the parabola y^(2)=...

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