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If a!=0 and the line 2b x+3c y+4d=0 pass...

If `a!=0` and the line `2b x+3c y+4d=0` passes through the points of intersection of the parabolas `y^2=4a x` and `x^2=4a y ,` then `d^2+(2b+3c)^2=0` `d^2+(3b+2c)^2=0` `d^2+(2b-3c)^2=0` none of these

A

`d^(2) +(3b-2c)^(2) =0`

B

`d ^(2) +(3b + 2c)^(2) =0`

C

`d ^(2) + (2b -3c)^(2) =0`

D

`d ^(2) + (2b+3c) ^(2) =0`

Text Solution

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The correct Answer is:
D
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