The joint equation of the straight lines...

The joint equation of the straight lines `x+y=1` and `x-y=4`, is

A

`x^(2)-y^(2)=-4`

B

`x^(2)-y^(2)=4`

C

`(x+y-1)(x-y-4)=0`

D

`(x+y+1)=(x-y+4)=0`

Text Solution

Verified by Experts

The correct Answer is:

C

NA

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Knowledge Check

The joint equation of the straight lines x-y=1 and 2x+y=6 is

A

`2x^(2)-y^(2)-xy-4x+7y-6=0`

B

`2x^(2)-y^(2)-xy-8x+5y+6=0`

C

`2x^(2)-y^(2)-xy+4x-7y-6=0`

D

`2x^(2)-y^(2)-xy+8x-5y+6=0`

Joint equation of the two lines x+y=1 and x-y=4 is

A

`x^(2)-y^(2)=-4`

B

`x^(2)-y^(2)=4`

C

`(x+y-1)(x-y-4)=0`

D

`(x+y+1)(x-y+4)=0`

Equation of the tangent to the circle at the point (1, -1) whose centre is the point of intersection of the straight lines x-y=1 and 2x+y-3=0, is

A

3x-y-4=0

B

x+4y+3=0

C

x-3y-4=0

D

4x+y-3=0

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The joints equation of the lines 3x-2y+5=0 and 5x-3y=0 is

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What is the equation of the straight line which passes through the point of intersection of the straight lines x+2y=5 and 3x+7y=17 and is perpendicular to the straight line 3x+4y=10 ?

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