The equation of the plane containing the line vecr=hati+hatj+lamda(2hati+hatj+4hatk) is
The lines barr=hati+2hatj+3hatk+lambda(hati+2hatj+3hatk)andbarr=-2hatj+hatk+lambda(2hati+2hatj-2hatk) are
The equation of the plane containing the lines vecr=(hati+hatj-hatk)+lamda(3hati-hatj) and vecr=(4hati-hatk)+mu(2hati+3hatk) , is
Find the vector and the Cartesian form of the equation of the plane containing two lines: vecr=hati+2hatj-hatk+lamda(2hati+3hatj+6hatk) and vecr= 3hati+3hatj-5hatk+mu(-2hati+3hatj+8hatk)
The vector equation of the plane containing he line vecr=(-2hati-3hatj+4hatk)+lamda(3hati-2hatj-hatk) and the point hati+2hatj+3hatk is
The vector equation of the plane barr=(2hati+hatk)+lamdahati+mu(hati+2hatj-3hatk) is
Find the shortest distance between the lines bar(r) = (4hati - hatj) + lamda(hati + 2hatj - 3hatk) and bar(r) = (hati - hatj + 2hatk) + mu(hati + 4hatj - 5hatk).
The equation of line passing throufh (3,-1,2) and perpendicular to the lines bar r =(hati + hatj -hatk )+ lamda (2 hati - 2 hatj +hatk ) and bar r =(2 hati + hatj - 3hatk )+ mu (hati -2 hatj + 2hatk ) is
