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If int1/((x^(2)-1))log((x-1)/(x+1))dx=A[...

If `int1/((x^(2)-1))log((x-1)/(x+1))dx=A[log((x-1)/(x+1))]^(2)+c`,
then A =

A

`1/2`

B

`1/3`

C

`1/4`

D

`1/6`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • int(1)/(x)log((1)/(x))dx=

    A
    `log(logx)+c`
    B
    `-(1)/(2)(logx)^(2)+c`
    C
    `2logx+c`
    D
    `-logx+c`

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