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intcos2thetalog((costheta+sintheta)/(cos...

`intcos2thetalog((costheta+sintheta)/(costheta-sintheta))d theta` is equal to

A

`(costheta-sintheta)^(2)log((costheta+sintheta)/(costheta-sintheta))+c`

B

`(costheta+sintheta)^(2)log((costheta+sintheta)/(costheta-sintheta))+c`

C

`(costheta-sintheta)^(2)/2log((costheta-sintheta)/(costheta+sintheta))+c`

D

`1/2sin2thetalogtan(pi/4+theta)-1/2log(sec2theta)+c`

Text Solution

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The correct Answer is:
D
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