intsec^(25//13)xcosec^(27//13)xdx=...

`intsec^(25//13)xcosec^(27//13)xdx=`

A

`-15/13(tanx)^(-15//13)+3/12(tanx)^(3//2)+c`

B

`-13/14(tanx)^(-14//13)+13/12(tanx)^(12//13)+c`

C

`-14/13(tanx)^(-13//14)+2/3(tanx)^(3//2)+c`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:

B

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