Home
Class 12
MATHS
The p.d.f. of a r.v. X is f(x)={{:(kx","...

The p.d.f. of a r.v. X is `f(x)={{:(kx","0ltxlt2),(0", otherwise"):}`, then k =

A

2

B

`1/2`

C

0

D

1

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • MHT-CET 2019 QUESTION PAPER

    TARGET PUBLICATION|Exercise Binomial Distribution|1 Videos

  • MHT-CET 2019 QUESTION PAPER

    TARGET PUBLICATION|Exercise Differential Equations|3 Videos

  • MATRICES

    TARGET PUBLICATION|Exercise EVALUATION TEST|13 Videos

  • MODEL QUESTION PAPER-I

    TARGET PUBLICATION|Exercise MCQs|48 Videos

Similar Questions

Explore conceptually related problems

The p.d.f. of a r.v. X is f(x)={{:(kx","0ltxlt2),(0", otherwise"):} , then P((1)/(4)ltXlt(1)/(3)) =

The p.d.f. of a r.v. X is f(x)={{:(0.5x","0ltxlt2),(0", otherwise"):} , then P(X le1) =

The p.d.f. of a r.v. X is f(x)={{:(0.5x", "0ltxlt2),(0", otherwise"):} , then P(X gt1.5) =

The p.d.f. of a r.v. X is f(x)={{:(0.5x", "0ltxlt2),(0", otherwise"):} , then P(0.5leXle1.5) =

The p.d.f. of a r.v. X is f(x)={{:(2x", "0lexle1),(0", otherwise"):} , then P((1)/(3)ltXlt(1)/(2)) =

The p.d.f. of a r.v. X is f(x)={{:(kx^(2)(1-x)","0ltxlt1),(0", otherwise"):} , then k =

The p.d.f. of a r.v. X is f_(X)(x)={{:(kx(1-x)","0ltXlt1),(0", otherwise"):} , then k =

The p.d.f. of a r.v. X is f_(X)(x)={{:(kx(1-x)","0ltXlt1),(0", otherwise"):} , then P((1)/(4)ltXlt(1)/(2)) =

The p.d.f. of a r.v. X is f(x)={{:(3(1-2x^(2))","0ltxlt1),(0", otherwise"):} , then F (x) =

The p.d.f. of a r.v. X is f_(X)(x)={{:(kx(1-x)","0ltXlt1),(0", otherwise"):} , then P(Xlt(1)/(2)) =

TARGET PUBLICATION-MHT-CET 2019 QUESTION PAPER -Probability Distribution
  1. The p.d.f. of a r.v. X is f(x)={{:(kx","0ltxlt2),(0", otherwise"):}, t...

    Text Solution

    |