Light of wavelength lambda(A) and lambda...

Light of wavelength `lambda_(A)` and `lambda_(B)` falls on two identical metal plates A and B respectively . The maximum kinetic energy of photoelectrons in `K_(A)` and `K_(B)` respectively , then which one of the following relations is true ? `(lambda_(A) = 2lambda_(B))`

`K_Alt(K_B)/(2)`

`2K_A=K_B`

`K_A=2K_B`

`K_Agt2K_B`

Text Solution

Verified by Experts

The correct Answer is:

Topper's Solved these Questions

ELECTRONS AND PHOTONS
TARGET PUBLICATION|Exercise Evaluation Test|19 Videos
ELECTRONS AND PHOTONS
TARGET PUBLICATION|Exercise Critical thinking|22 Videos
COMMUNICATION SYSTEMS
TARGET PUBLICATION|Exercise Evaluation Test|15 Videos
FORCE
TARGET PUBLICATION|Exercise Evaluation Test|16 Videos

Similar Questions

Explore conceptually related problems

Two identical metal plates show photoelectric effect. Light of wavelength lamda_A falls on plate A and lamda_B fall on plate B lama_A=2lamda_B , The maximum KE of the photoelectrons are K_A and K_B , respectively, Which one of the following is true?

Let K_(1) be the maximum kinetic energy of photoelectrons emitted by a light of wavelength lambda_(1) and K_(2) corresponding to lambda_( 2). If lambda_(1) = 2lambda_(2) , then

When photones of energy 4.0 eV fall on the surface of a metal A, the ejected photoelectrons have maximum kinetic energy T_(A) ( in eV) and a de-Broglie wavelength lambda_(A) . When the same photons fall on the surface of another metal B, the maximum kinetic energy of ejected photoelectrons is T_(B) = T_(A) -1.5eV . If the de-Broglie wavelength of these photoelectrons is lambda_(B) =2 lambda _(A) , then the work function of metal B is

Let be the maximum kinetic energy of photoelectrons emitted by light of wavelength lambda_(1) and lambda_(2) correspondingto wavelength lambda_(2) . If lambda_(1) = 2lambda_(2) then:

If K_(1) and K_(2) are maximum kinetic energies of photoelectrons emitted when light of wavelength lambda_(2) and lambda_(1) respectively are incident on a metallic surface. If lambda_(1)=3lambda_(2) then

TARGET PUBLICATION-ELECTRONS AND PHOTONS-Competitive Thinking

The momentum of a photon is 2 xx 10^(-16) gm - cm//sec. Its energy is
Text Solution
|
If the energy of a photon corresponding to a wavelength of 6000 Å is 3...
Text Solution
|
If we express the energy of a photon in KeV and the wavelength in angs...
Text Solution
|
A metal surface of work function 1.07 eV is irradiated with light of w...
Text Solution
|
The work function of metal is 1 eV. Light of wavelength 3000 Å is inc...
Text Solution
|
Energy from the sun is recived on earth at the rate of 2 cal per cm^(2...
Text Solution
|
when a monochromatic point source of light is at a distance 0.2 m from...
Text Solution
|
When a metal surface is illuminated by light wavelengths 400 nm and 25...
Text Solution
|
The velocity of the most energetic electrons emitted from a metallic s...
Text Solution
|
A modern 200 W sodium street lamp emits yellow light of wavelength 0.6...
Text Solution
|
Ultraviolet light of wavelength 300nn and intensity 1.0Wm^-2 falls on ...
Text Solution
|
The number of photons falling per second on a completely darkened plat...
Text Solution
|
Photoelectric emission is observed from a metallic surface for frequen...
Text Solution
|
A photoelectric surface is illuminated successively by monochromatic l...
Text Solution
|
Two identical photo-cathodes receive light of frequencies v1 and v2. ...
Text Solution
|
A metal surface is illuminated by light of two different wavelengths 2...
Text Solution
|
A photon of energy E ejects a photoelectron from a metel surface whose...
Text Solution
|
Light of wavelength lambda(A) and lambda(B) falls on two identical met...
Text Solution
|
The energy of the electromagetic wave is of the order of 15 keV. To wh...
Text Solution
|
The photoelectric work function of a surface is 2.2 eV. The maximum ki...
Text Solution
|