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Relation between the stopping potential ...

Relation between the stopping potential `V_0` of a metal and the maximum velocity of the photoelectrons is

A

`V_0prop(1)/(v)`

B

`V_0prop(1)/(v^2)`

C

`V_0 propv^2`

D

`V_0=v`

Text Solution

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The correct Answer is:
C
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Knowledge Check

  • When ultraviolet light is incident on a photocell, its stopping potential is V_(0) and the maximum kinetic energy of the photoelectrons is K_(max) . When X-rays are incident on the same cell, then:

    A
    `V_(0)` and `K_(max)` both increase
    B
    `V_(0)` and `K_(max)` both decrease
    C
    `V_(0)` increases but `K_(max)` remains the same
    D
    `K_(max)` increases but `V_(0)` remains the same

  • if e/m of electron is 1.76xx10^(11)C(kg)^(-1) andn stopping potential is 0.71 V, then the maximum velocity of the photoelectron is

    A
    `150kms^(-1)`
    B
    `200kms^(-1)`
    C
    `500kms^(-1)`
    D
    `250kms^(-1)`

  • Photons of energy 2.0eV fall on a metal plate and release photoelectrons with a maximum velocity V . By decreasing lambda and 25% the maximum velocity of photoelectrons is doubled. The work function of the metal of the material plate in eV is nearly

    A
    `2.22`
    B
    `1.985`
    C
    `2.35`
    D
    `1.80`

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    If in a photoelectric experiment, the stopping potential is 1.5 volts, what is the maximum kinetic energy of a photoelectrons?

    How is the stopping potential in volt related to the maximum kinetic energy of photoelectrons in electron volt?

    Choose the graph showing the correct relationship between the stopping potential V_0 and the frequency v of light for potassium and tungsten.

    Assertion: If the maximum kinetic energy of electrons emitted by a photo cell is 5 eV, then the stopping potential is 5 V. Reason: Stopping potential for fastest photoelectrons is numerically equal to their kinetic energy.

    For a certain metal , v is five times the v_(0) and the maximum velocity of coming out photo electrons is 8 xx 10^(8) If v = 2_(v_(0)) , the maximum velocity of photo electrons will be .

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